Second Law of Thermodynamics

The statement "It is impossible to construct a device that operates on a cycle and produce no other effect than doing work and transfer of heat" is given by

Write Kelvin Planck's statements of the second law of thermodynamics.

The refrigerator works on Clausius' statements of the second law of thermodynamics.

The statement "The transfer of the heat is impossible without any work" is given by

Write Clausius' statement of the second law of thermodynamics.

The first law of thermodynamics tells about the process.

The first law of the thermodynamics tells about the direction of flow of heat.

A heat engine absorbs heat ${\mathrm{Q}}_1$ at temperature ${\mathrm{T}}_1$ and heat ${\mathrm{Q}}_2$ at temperature ${\mathrm{T}}_2$. Work done by the engine is $\left({\mathrm{Q}}_1+{\mathrm{Q}}_2\right) \mathrm{J}$. This data

The $\mathrm{SI}$ unit of $∆\mathrm{S}$ is 

Calculate the melting point of $\mathrm{KCl}\left(\mathrm{s}\right)$ from the data, ${∆}_{\mathrm{fus}}\mathrm{H}\left(\mathrm{KCl}\right)=7.25 \mathrm{kJ} {\mathrm{mol}}^{-1}$ and ${∆}_{\mathrm{fus}}\mathrm{S}\left(\mathrm{KCl}\right)=7 \mathrm{J} {\mathrm{K}}^{-1} {\mathrm{mol}}^{-1}$.

What is the sign of $∆\mathrm{S}$ for the following reaction?

${\mathrm{CaCO}}_3\left(\mathrm{s}\right)\stackrel{ }{\to }\mathrm{CaO}\left(\mathrm{s}\right)+{\mathrm{CO}}_2\left(\mathrm{g}\right)$

What does entropy measure?

For the reaction, ${\mathrm{Fe}}_2{\mathrm{O}}_3\left(\mathrm{s}\right)+3\mathrm{CO}\left(\mathrm{g}\right)\stackrel{ }{\to }2\mathrm{Fe}\left(\mathrm{s}\right)+3{\mathrm{CO}}_2\left(\mathrm{g}\right); ∆{\mathrm{H}}^{\circ }=-28.4 \mathrm{kJ}$ at $298 \mathrm{K}$. Calculate the change in entropy.

Write any two applications of 'second law of thermodynamics'.

The change in entropy at equilibrium is 

Define entropy and write its $\mathrm{SI}$ unit.

Which of the following statement is NOT correct, according to second law of thermodynamics?

The criterion of spontaneity in terms of Gibbs energy is the same as that laid down by second law of thermodynamics. How?

State second law of thermodynamics in terms of entropy and express it mathematically.

Enthalpy ($∆$H) for the reaction, $\mathrm{Zn}+2\mathrm{AgCl}\to {\mathrm{ZnCl}}_2+2\mathrm{Ag}\mathrm{ }\mathrm{at} 300 \mathrm{K} \mathrm{temperature} \mathrm{is}-218\mathrm{ }\mathrm{KJ}/\mathrm{mole}$ and emf of the cell was $1.015\mathrm{ }\mathrm{V}\cdot \mathrm{Then} \mathrm{the} \mathrm{vaule} \mathrm{of} {\left(\frac{\mathrm{dE}}{\mathrm{dT}}\right)}_{\mathrm{p}}$ of the cell is?